16-(x+(3/x))^2=0

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Solution for 16-(x+(3/x))^2=0 equation:


D( x )

x = 0

x = 0

x = 0

x in (-oo:0) U (0:+oo)

16-(x+3/x)^2 = 0

16-1*(x+3*x^-1)^2 = 0

16-1*(x+3*x^-1)^2 = 0

10-x^2-9*x^-2 = 0

10-x^2-9*x^-2 = 0

10*x^0-1*x^2-9*x^-2 = 0

(10*x^2-1*x^4-9*x^0)/(x^2) = 0 // * x^4

x^2*(10*x^2-1*x^4-9*x^0) = 0

x^2

10*x^2-x^4-9 = 0

{ 1, -1, 3, -3, 9, -9 }

1

x = 1

10*x^2-x^4-9 = 0

1

x-1

9*x-x^3-x^2+9

10*x^2-x^4-9

x-1

x^4-x^3

10*x^2-x^3-9

x^3-x^2

9*x^2-9

9*x-9*x^2

9*x-9

9-9*x

0

9*x-x^3-x^2+9 = 0

{ 1, -1, 3, -3, 9, -9 }

1

x = 1

9*x-x^3-x^2+9 = 16

1

-1

x = -1

9*x-x^3-x^2+9 = 0

-1

x+1

9-x^2

9*x-x^3-x^2+9

x+1

x^3+x^2

9*x+9

-9*x-9

0

9-x^2 = 0

DELTA = 0^2-(-1*4*9)

DELTA = 36

DELTA > 0

x = (36^(1/2)+0)/(-1*2) or x = (0-36^(1/2))/(-1*2)

x = -3 or x = 3

x in { -3, 3, 1, -1}

(x+3)*(x-3)*(x-1)*(x+1) = 0

(x+3)*(x-3)*(x-1)*(x+1) = 0

( x+1 )

x+1 = 0 // - 1

x = -1

( x+3 )

x+3 = 0 // - 3

x = -3

( x-1 )

x-1 = 0 // + 1

x = 1

( x-3 )

x-3 = 0 // + 3

x = 3

x in { -1, -3, 1, 3 }

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